Python使用Pandas对列表赋值循环该怎么办？？
论文问答
1
def fuzhi(x):
i=0
for x in df3['str']:
x==i
i=i+1
print(i)
if i>=len(df3['str']):
break
df3.loc[:,"strlist"] = df3.apply(fuzhi,axis=1)
用这段代码，陷入了死循环
该怎么实现下边这样的效果，也就是生成strlist这一列，比如第一个数据a，他就是0，然后再次出现在str这一列，他还是0，以此类推；b是1，再次出现在str这一列，还是1
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import pandas as pd from pandas.core.frame import DataFrame def getValue(rawList): num = 0 newDict = {} strList = [] for i in rawList: if i not in strList: newDict[i] = num strList.append(i) num += 1 resultList = [newDict[b] for b in rawList] newDataFrame = DataFrame({"str":rawList, "strlist":resultList}) print(newDataFrame) #data = pd.read_table("test") #将你的str列转换成列表 rawList = data['str'].tolist() #getValue(['a', 'b', 'c', 'a', 'd', 'c', 'b', 'a', 'e']) getValue(rawList) -
import pandas as pd from pandas.core.frame import DataFrame def getValue(rawList): num = 0 newDict = {} strList = [] for i in rawList: if i not in strList: newDict[i] = num strList.append(i) num += 1 resultList = [newDict[b] for b in rawList] newDataFrame = DataFrame({"str":rawList, "strlist":resultList}) print(newDataFrame) #data = pd.read_table("test") #将你的str列转换成列表 rawList = data['str'].tolist() #getValue(['a', 'b', 'c', 'a', 'd', 'c', 'b', 'a', 'e']) getValue(rawList)
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